(2x-y^2)(2y-4x-3y^2)=0

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Solution for (2x-y^2)(2y-4x-3y^2)=0 equation: 


Simplifying
(2x + -1y2)(2y + -4x + -3y2) = 0

Reorder the terms:
(2x + -1y2)(-4x + 2y + -3y2) = 0

Multiply (2x + -1y2) * (-4x + 2y + -3y2)
(2x * (-4x + 2y + -3y2) + -1y2 * (-4x + 2y + -3y2)) = 0
((-4x * 2x + 2y * 2x + -3y2 * 2x) + -1y2 * (-4x + 2y + -3y2)) = 0

Reorder the terms:
((4xy + -6xy2 + -8x2) + -1y2 * (-4x + 2y + -3y2)) = 0
((4xy + -6xy2 + -8x2) + -1y2 * (-4x + 2y + -3y2)) = 0
(4xy + -6xy2 + -8x2 + (-4x * -1y2 + 2y * -1y2 + -3y2 * -1y2)) = 0
(4xy + -6xy2 + -8x2 + (4xy2 + -2y3 + 3y4)) = 0

Reorder the terms:
(4xy + -6xy2 + 4xy2 + -8x2 + -2y3 + 3y4) = 0

Combine like terms: -6xy2 + 4xy2 = -2xy2
(4xy + -2xy2 + -8x2 + -2y3 + 3y4) = 0

Solving
4xy + -2xy2 + -8x2 + -2y3 + 3y4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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